Answer
$x^{2}+9x+20$
Work Step by Step
Given : $\frac{p}{x^{2}+x-12} = \frac{x+5}{x-3}$
Thus,
$p=\frac{(x+5)(x^{2}+x-12)}{(x-3)}= \frac{(x+5)(x+4)(x-3)}{(x-3)}=(x+5)(x+4)$
$=x^{2}+9x+20$
(After dividing out the common factor (x-3))
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