Answer
$\frac{(2r−1)}{(r+5)}$
The denominator is zero when r=-5.
Work Step by Step
Converting numerator and denominator from quadratic equation into a product of two linear equations, we get $\frac{(2r−1)(r+5)}{(r+5)(r+5)}$, and upon simplifying, we get $\frac{(2r−1)}{(r+5)}$,
The denominator is zero when r=-5.