Answer
$\frac{x^2-9}{x+3}$ is the same as $x-3$.
Work Step by Step
$\frac{x^2-9}{x+3}$
$=\frac{(x+3)(x-3)}{x+3}$
Simplify:
$=x-3$
Hence, $\frac{x^2-9}{x+3}$ is the same as $x-3$.
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