Answer
6x+6
Work Step by Step
First, find the area of Rectangle A with the Area = Length x Width formula. Then multiply 2x+6 by -3x and distribute: ((2x)(3x) + (6)(3x)) = $6x^{2}$ + 18x.
The area of Rectangle A is $6x^{2}$ + 18x.
Rectangle B's area is 12 square units greater than Rectangle A, so add 12 to the equation used for the area of Rectangle A.
$6x^{2}$ + 18x + 12
To find the width of Rectangle B factor the equation for its area.
$6x^{2}$ + 18x + 12
$6(x^{2}$ + 3x + 2)
6(x+2)(x+1)
After simplifying, divide the area of Rectangle B by its length x+2.
6(x+2)(x+1) $\div$ (x+2) = 6(x+1)
Distribute to get the width of Rectangle B.
6(x+1) = 6x+6
