Answer
$-\frac{2a+1}{a+3}$
Work Step by Step
(Factor -1 from the denominator)
$\frac{4a^{2}-8a-5}{-1(2a^{2}+a-15)}$
(Factor the quadratic in the numerator)
$\frac{(2a+1)(2a-5)}{-1(2a^{2}+a-15)}$
(Factor the quadratic in the denominator)
$\frac{(2a+1)(2a-5)}{-1(2a-5)(a+3)}$
(Divide by the common factor 2a-5)
$-\frac{2a+1}{a+3}$
