Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 42

Answer

$r=1$

Work Step by Step

$2\sqrt r=\sqrt 3r+1$ Square both sides: $4r=3r+1$ $r=1$ Check: $2\sqrt 1=\sqrt 3(1)+1$ $2=2$ The solution is $r=1$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.