Answer
$=-2+\sqrt 3$
Work Step by Step
Applying the rules of radicals:
$\frac{\sqrt 3-3}{\sqrt 3+3}$
Multiply each side with $\frac{\sqrt 3-3}{\sqrt 3-3}$
$=\frac{(\sqrt 3-3)^2}{3-9}$
$=\frac{3 -6\sqrt 3+9}{-6}$
$=-2+\sqrt 3$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 35
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