Answer
$=4+2\sqrt 3$
Work Step by Step
Applying the rules of radicals:
$\sqrt 2(\sqrt 8+\sqrt 6)$
$=\sqrt 16+\sqrt 12$
$=4+2\sqrt 3$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 32
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