Answer
$-\frac{3\sqrt 2+9}{7}$
Work Step by Step
Applying the rules of radicals:
$\frac{3}{\sqrt 2-3}$
Multiply each side with $\frac{\sqrt 2+3}{\sqrt 2+3}$
$=\frac{3(\sqrt 2+3)}{2-9}$
$=-\frac{3\sqrt 2+9}{7}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 34
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