Answer
The solution is $d=2$.
Work Step by Step
$\sqrt 2+d=d$
Square both sides:
$2+d=d^2$
$d^2-d-2=0$
$(d-2)(d+1)=0$
$d-2=0$ or $d+1=0$
$d=2$ or $d=-1$
Check:
$\sqrt 2+2=2$
$2=2$
$\sqrt 2+(-1)=-1$
$1 \ne -1$
The solution is $d=2$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 41
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