University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises - Page 296: 9.22

Answer

(a) $d = 5.09~cm$ (b) $\alpha = 15.72~rad/s^2$

Work Step by Step

(a) The distance of one revolution is $\pi~d$, where $d$ is the diameter of the axle. In one minute, the bucket moves $(2.00~cm/s)(60~s)$ which is 120 centimeters. We can find the diameter $d$ of the axle. $(7.5~rpm)(\pi~d) = 120~cm$ $d = \frac{120~cm}{(7.5~rpm)(\pi)}$ $d = 5.09~cm$ (b) $\alpha = \frac{a}{r} = \frac{0.400~m/s^2}{(\frac{0.0509~m}{2})}$ $\alpha = 15.72~rad/s^2$
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