Answer
(a) $v = 1.66~m/s$
(b) $a_{rad} = 217~m/s^2$
Work Step by Step
(a) The maximum linear speed will be a point on the edge of the drill bit.
$v = (1250~rev/min)(2\pi ~r)(\frac{1~min}{60~s})$
$v = (1250~rev/min)(2\pi)(0.0127~m)(\frac{1~min}{60~s})$
$v = 1.66~m/s$
(b) The maximum radial acceleration will be at a point on the edge of the drill bit.
$a_{rad} = \frac{v^2}{r} = \frac{(1.66~m/s)^2}{0.0127~m}$
$a_{rad} = 217~m/s^2$
