University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises - Page 295: 9.13

Answer

$\omega_0 = 3.00~rad/s$

Work Step by Step

$\theta = \omega_0 ~t + \frac{1}{2}\alpha ~t^2$ $\omega_0 = \frac{\theta -\frac{1}{2}\alpha ~t^2}{t}$ $\omega_0 = \frac{(30.0~rad) -\frac{1}{2}(2.25~rad/s^2)(4.00~s)^2}{4.00~s}$ $\omega_0 = 3.00~rad/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.