Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 2 - Energy, Energy Transfer, and General Energy Analysis - Problems - Page 97: 2-11

Answer

It can generate 2.824MJ/s or 2.824MW power

Work Step by Step

Assuming the total conversion of the water potential energy into the kinetic and eventually electrical energy, per second. h= 120m m= 2400kg/s g= 9.807 E= $\Delta$PE $\Delta$PE = mgh $\Delta$PE = $2400 \times 9.807 \times 120$ $\Delta$PE = 2824kj 2824kj = 2.824Mj/s j/s=W 2824kj = 2.824MW powe
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