Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 2 - Energy, Energy Transfer, and General Energy Analysis - Problems - Page 97: 2-9E

Answer

2.57Btu

Work Step by Step

Use the formula for the total potential energy PE=mgz=(200lbm)$\times$(32.2ft$/s^{2}$)$\times$(10ft)($\frac{1Btu/lbm}{25,037ft^{2}/s^{2}}$) =2.57Btu
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