Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 2 - Energy, Energy Transfer, and General Energy Analysis - Problems - Page 97: 2-10

Answer

10.297kj

Work Step by Step

The potential energy increased in the suitcase comes from the electrical energy consumed by motor. m = 30kg g = 9.807m/$s^{2}$ h = 35m Energy consumed by motor ΔPE = mgh $\Delta$PE= $30\times35\times9.807$ $\Delta$PE= 10.297kj
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