Chapter 4 - Two-Dimensional Kinematics - Problems and Conceptual Exercises - Page 104: 2

(a) $5340m$ (b) $3330m$

(a) We can find the required distance traveled along the west as $x=v_xt$ We plug in the known values to obtain: $x=(3.56m/s)(1500s)$ $x=5340m$ (b) We can find the distance traveled towards north as $y=v_yt$ We plug in the known values to obtain: $y=(2.22m/s)(1500s)$ $\implies y=3330m$