Answer
$\textbf{(a)}$ Distance: $L=9.9\text{ m}$.
$\textbf{(b)}$ $AB=1\text{ m}$.
Work Step by Step
$\textbf{(a)}$ Your distance from the second base is the same as your distance from the point $A$ which is the same as the distance that the ball travels in the horizontal direction. Because the horizontal component of the velocity is constant $v_h=22\text{ m/s}$ then this distance is
$$L=v_h\cdot t=22\text{ m/s }\cdot0.45\text{ s}=9.9\text{ m}.$$
$\textbf{(b)}$ The vertical drop is due to gravitational acceleration:
$$AB=\frac{1}{2}gt^2=\frac{1}{2}\cdot9.81\text{ m/s}^2\cdot0.45^2\text{ s}^2=1\text{ m}.$$
