Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 4 - Two-Dimensional Kinematics - Problems and Conceptual Exercises - Page 104: 12

Answer

The required speed is: $$v=7.9\text{ m/s}.$$

Work Step by Step

The horizontal component of the velocity constant, i.e. $$v_h=1.85\text{ m/s},$$ The vertical component is due to the gravitational acceleration, and since there is no initial speed in this direction we have for the final vertical component: $$v_v=\sqrt{2gh}.$$ The final speed is thus: $$v=\sqrt{v_h^2+v_v^2}=\sqrt{v_h^2+2gh}=\sqrt{1.85^2+2\cdot9.81\cdot 3.00}\text{ m/s}=7.9\text{ m/s}.$$
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