Answer
$K = 18.53$
Work Step by Step
We have
$T_1 = 20^oC = 293K$
$T_2 = 5^oC = 278K$
Therefore
$K = \frac{T_2}{T_1-T_2}$
$K = \frac{278K}{293K-278K}$
$K = 18.53$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 21 - Heat Engines and Refrigerators - Exercises and Problems - Page 594: 8
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