Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 21 - Heat Engines and Refrigerators - Exercises and Problems - Page 594: 1

Answer

$ \eta = 33.33\%$

Work Step by Step

We know that $ W=Q_1 -Q_2$ $200J = Q_1 -400J$ $ Q_1 = 600J$ Also $ \eta = \frac{W}{Q_1}$ $\eta = \frac{200J}{600J}$ $ \eta = 33.33\%$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.