Answer
a)$Q_1 =250J$
b)$Q_2 = 150J$
Work Step by Step
a)We have
$ \eta = \frac{W}{Q_1}$
$ 40\% = \frac{100J}{Q_1}$
$ Q_1 = 100J *\frac{100}{40}$
$Q_1 =250J$
b) Also $ W=Q_1 -Q_2$
$ 100J = 250J -Q_2$
$Q_2 = 150J$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 21 - Heat Engines and Refrigerators - Exercises and Problems - Page 594: 2
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