Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 21 - Heat Engines and Refrigerators - Exercises and Problems - Page 594: 6

Answer

95625 houses

Work Step by Step

We have $\eta = \frac{Q_1- Q_2}{Q_1}$ Dividing numerator and denominator on right side by $t$ we get $\eta = \frac{P_1 -P_2}{P_1}$ $0.32 = \frac{900MW } { P1}$ $ P_1 = 2812.5 MW$ Now $ P_1 -P-2 = 900MW$ $ 2812.5MW - P_2 = 900Mw $ $P_2 = 1912.5MW$ Power used by house is $20kW$. Therefore total number of houses which could be heated from waste heat is $ n= 1912.5MW/20kW$ $n= 95625 houses$
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