Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 31 - Nuclear Physics and Radioactivity - Problems - Page 899: 3

Answer

(a) element name is platinum so $X=Pt$. Number of neutron $N=117$ (b) element name is Sulphur so $X=S$. Number of neutron $N=16$ (c) element name is Copper so $X=Cu$. Number of neutron $N=34$ (d)element name is Boron so $X=B$. Number of neutron $N=6$ (e)element name is Plutonium so $X=Pu$. Number of neutron $N=145$

Work Step by Step

(a) $ ^{195}_{78}X$ Comparing with $ ^{A}_{Z}X$ we get $A=195$ $Z=78$ element name is Platinum so $X=Pt$ number of neutrons $N=A-Z$ $N=195-78=117$ no of neutron $N=117$ (b) $ ^{32}_{16}X$ Comparing with $ ^{A}_{Z}X$ we get $A=32$ $Z=16$ element name is Sulphur so $X=S$ number of neutrons $N=A-Z$ $N=32-16=16$ no of neutron $N=16$ (c) $ ^{63}_{29}X$ Comparing with $ ^{A}_{Z}X$ we get $A=63$ $Z=29$ element name is Copper so $X=Cu$ number of neutrons $N=A-Z$ $N=63-29=6$ no of neutron $N=34$ (d) $ ^{11}_{5}X$ Comparing with $ ^{A}_{Z}X$ we get $A=11$ $Z=5$ element name is Boron so $X=B$ number of neutrons $N=A-Z$ $N=11-5=6$ no of neutron $N=6$ (e) $ ^{239}_{94}X$ Comparing with $ ^{A}_{Z}X$ we get $A=239$ $Z=94$ element name is Plutonium so $X=Pu$ number of neutrons $N=A-Z$ $N=239-94=145$ no of neutron $N=145$
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