Answer
Yes, 76 m further
Work Step by Step
$a=\frac{v-u}{t}$
a) $a_{j}=\frac{3.0-0}{2.0}$ = 1.5 $m/s^{2}$
b) $a_{c}=\frac{41.0-38.0}{2.0}$ = 1.5 $m/s^{2}$
c)
$x=\frac{1}{2}(u+v)t$
$x_{j}=\frac{1}{2}(0+3.0)(2.0)$ = 3.0 m
$x_{c}=\frac{1}{2}(38.0+41.0)(2.0)$ = 79 m
Car travels 79-3.0 = 76 m further
