Answer
Cycle A was initially travelling 8 m/s faster
Work Step by Step
u = v - at
$u_{A}$ = v - (2.0)(4) = v-8
$u_{B}$ = v - (4.0)(4) = v-16
Difference in initial speeds = (v-8) - (v-16) = 8 m/s
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 2 - Kinematics in One Dimension - Problems - Page 48: 23
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