Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 48: 11

Answer

6.76 m/s due north

Work Step by Step

distance = speed $\times$ time a) $d_{1}$ = 7.2 $\times$ (22 $\times$ 60) = 9504 m $d_{2}$ = 5.1 $\times$ (36 $\times$ 60) = 11 016 m $d_{3}$ = 13 $\times$ (8 $\times$ 60) = 6240 m Total distance = 9504 + 11 016 + 6240 = 26 760 m b) Total time = (22 + 36 + 8) $\times$ 60 = 3960 s Average velocity = displacement / time = 26 760 / 3960 = 6.76 m/s due north
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