Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 11 - Fluids - Problems - Page 312: 73

Answer

32.9 m/s

Work Step by Step

Let's apply Bernoulli's equation to find the wind speed. $P+\frac{1}{2}\rho v^{2}+\rho gh= constant$ $P_{out}+\frac{1}{2}\rho v^{2}+0=P_{in}+0+0$ $P_{in}-P_{out}=\frac{1}{2}(1.29\space kg/m^{3})v^{2}-(1)$ We know that, $P=\frac{Force}{Area}$ So, we can write $P_{in}-P_{out}=\frac{22000\space N}{(5\times6.3\space m^{2})}=698.4\space Pa-(2)$ (2)=>(1), $v_{2}=\sqrt {\frac{2\times698.4\space Pa}{1.29\space kg/m^{3}}}=32.9\space m/s$ So, Wind speed = 32.9 m/s
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