Answer
$3\times10^{5}Pa$
Work Step by Step
Let's apply Bernoulli's equation to find the desired pressure $P_{2}$
$P+\frac{1}{2}\rho v^{2}+\rho gh= constant$
$3\times10^{5}Pa+\frac{1}{2}(1000\space kg/m^{3})(2.1\space m/s)^{2}+0=P_{2}+\frac{1}{2}(1000\space kg/m^{3})(3.7\space m/s)^{2}+(1000\space kg/m^{3})(9.8\space m/s^{2})(4\space m)$
$P_{2}\approx3\times10^{5}Pa$
