Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 11 - Fluids - Problems - Page 309: 22

Answer

(a) 99536 Pa (b) 100124 Pa

Work Step by Step

(a) By considering the pressure in the same elevation we can write. $P_{B}+h\rho g=P_{0}$ $P_{B}=P_{0}-h\rho g$ ; Let's plug known values into this equation. $P_{B}=1.013\times10^{5}\space Pa -0.15\space m\times 1200\space kg/m^{3}\times9.8\space m/s^{2}=99536\space Pa$ When the height of the sauce = 0.15 m , the absolute pressure of the bulb = 99536 Pa (b) Similarly, $P_{B}=P_{0}-h\rho g$ ; Let's plug known values into this equation. $P_{B}=1.013\times10^{5}\space Pa -0.1\space m\times 1200\space kg/m^{3}\times9.8\space m/s^{2}=100124\space Pa$ When the height of the sauce = 0.1 m, the absolute pressure of the bulb = 100124 Pa
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