Answer
Force required to pull lid is $F=1.105\times10^{3}N$ or $1105N$
Work Step by Step
Area of the removable lid is $A=1.3\times10^{-2}m^2$
The pressure outside of the box $P=0.85\times10^{5}Pa=0.85\times10^{5}N/m^2$
since $P=\frac{F}{A}$
so force required to pull the lid will be $F=PA$
$F=0.85\times10^{5}N/m^2\times1.3\times10^{-2}m^2$
$F=1.105\times10^{3}N$ or $1105N$
