Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 10 - Simple Harmonic Motion and Elasticity - Problems - Page 279: 83

Answer

140 N/m

Work Step by Step

Let's apply the equation $\omega=\sqrt {\frac{k}{m}}$ to find the value of k. $\omega=\sqrt {\frac{k}{m}}=>k=\omega^{2}m-(1)$ We know that, $T=\frac{2\pi}{\omega}=>\omega=\frac{2\pi}{T}-(2)$ (2)=>(1), $k=(\frac{2\pi}{T})^{2}m$ ; Let's plug known values into this equation. $k=\frac{4\pi^{2}\times82\space kg}{4.8^{2}\space s^{2}}\approx140\space N/m$
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