Answer
$1.4\times10^{-6}$
Work Step by Step
Let's use equation 10.20 $\frac{\Delta V}{V_{0}}=-\frac{\Delta P}{B}$ to find the solution.
$\frac{\Delta V}{V_{0}}=-\frac{(-1.01\times10^{5}Pa)}{7.1\times10^{10}N/m^{2}}\approx1.4\times10^{-6}$
Here the value of the bulk modulus B of Aluminum was taken from table 10.3
