Answer
$v=7.38m/s$
Work Step by Step
$K + E_{th} = U$
$\frac{1}{2}mv^2 +fd=mgd$
$\frac{1}{2}mv^2 =mgd -fd$
$v=\sqrt {\frac{2(mgd -fd)}{m}}$
$v=\sqrt {\frac{2d(mg -f)}{m}}$
$v=\sqrt {\frac{(2)(3.7)(1800\times 9.8 -4.4)}{1800}}$
$v=7.38m/s$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 207: 63a
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