Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 207: 60

Answer

$d = 4.3m$

Work Step by Step

$K_i= U + E_{th}$ $K_i= mgdsin\theta + f_kd$ $K_i= d(mgsin\theta + μ_kmgcos\theta)$ $K_i= dmg(sin\theta + μ_kcos\theta)$ $d = \frac{K_i}{2mg(sin\theta + μ_kcos\theta)}$ $d = \frac{K_i}{2mg(sin\theta + μ_kcos\theta)}$ $d = \frac{128}{(2)(4)(9.8)(sin30^{\circ} + 0.3\times cos30^{\circ})}$ $d = 4.3m$
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