Answer
They remain the same
Work Step by Step
In Problem 14a, we used
$v_{0} = \sqrt {v^{2} + 2g\Delta h}$
to find the initial speed.
In Problems 14b and 14c, we used
$v = \sqrt {v_{0}^{2} – 2g\Delta h}$
to find the final speeds.
Both expressions for the velocities do not involve the mass $m$ of the ball. Therefore, all the answers would remain the same.
