Answer
-0.052 J
Work Step by Step
As $x_{i}=0$, work done by the spring force is given by
$W_{s}=-\frac{1}{2}kx^{2}=-\frac{1}{2}\times\frac{18.0\,N}{10^{-2}m}\times(7.60\times10^{-3}\,m)^{2}=-0.052\,J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 7 - Kinetic Energy and Work - Problems - Page 176: 83a
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