Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 176: 81e

Answer

The position where the power is maximum can be found by differentiating $P$ with respect to $x$ , setting $d P / d x=0$ : $$ \frac{d P}{d x}=\frac{k^{2}\left(x_{i}^{2}-2 x^{2}\right)}{\sqrt{\frac{k\left(x_{i}^{2}-2 x^{2}\right)}{m}}}=0 $$ which gives $x=\frac{x_{i}}{\sqrt{2}}=\frac{(0.300 \mathrm{m})}{\sqrt{2}}=0.212 \mathrm{m}$

Work Step by Step

The position where the power is maximum can be found by differentiating $P$ with respect to $x$ , setting $d P / d x=0$ : $$ \frac{d P}{d x}=\frac{k^{2}\left(x_{i}^{2}-2 x^{2}\right)}{\sqrt{\frac{k\left(x_{i}^{2}-2 x^{2}\right)}{m}}}=0 $$ which gives $x=\frac{x_{i}}{\sqrt{2}}=\frac{(0.300 \mathrm{m})}{\sqrt{2}}=0.212 \mathrm{m}$
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