Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1306: 71a

Answer

$\Delta E = 6.6 \times 10^6 eV$

Work Step by Step

The equation of uncertainty equation $\Delta E = \frac{\hbar}{T_{Ave}}$ $\Delta E = \frac{1.055 \times 10^{-34} Js }{1.0 \times 10^{-22} s}$ $\Delta E = 1.0546 \times 10^{-12} J$ Change to eV. $\Delta E = 1.0546 \times 10^{-12} J (\frac{1 \space eV}{1.602 \times 10^{-19} J})$ $\Delta E = 6.6 \times 10^6 eV$
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