Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1306: 67

Answer

$D = 0.0025 \space Sv= 2.5 \space mSv$

Work Step by Step

To find the absorbed dose, energy in joule is divided by mass of subject. Absorbed dose, $D = \frac{E}{m}$ $D = \frac{2.0 \times 10^{-3} J }{4.0 kg}$ $D = 5.00 \times 10^{-4} J/kg$ *Note that 1 J/kg = 1 Gy $D = 5.00 \times 10^{-4} Gy$ To find the answer in Sv, The dose of $5.00 \times 10^{-4} Gy$ must be multiplied by the relative biological effectiveness, $RBE = 5$ $D = (5.00 \times 10^{-4} Gy)(5)$ $D = 0.0025 \space Sv= 2.5 \space mSv$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.