Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1306: 68a

Answer

$E = 0.018 \space J = 18 \space mJ$

Work Step by Step

The energy absorbed is given by mass of a person $m$ multiplied by dose given $D$ $E = mD$ $E = (75 kg) (2.4 \times 10^{-4} Gy)$ $E = 0.018 \space J = 18 \space mJ$
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