Answer
$\Big(\frac{h}{8mL^2}\Big)$
Work Step by Step
The frequency $(v)$ that corresponds to photon energy $(E)$ is given by
$v=\frac{E}{h}$
From the section $(a)$ of this problem, we can say that the lowest frequency occurs at $E_{2,2,2}\leftrightarrow E_{3,1,1}$ tranision. The correspond frequency is
$v=\frac{\Delta E}{h}=\Big(\frac{h}{8mL^2}\Big)$
