Answer
$\beta=2.23T$
Work Step by Step
We know that
$\beta=\frac{\gamma \space mv}{qR}$
We plug in the known values to obtain:
$\beta=\frac{534.049\times 1.67\times 10^{-27}\times 0.99999824689\times 3\times 10^8}{1.6\times 10^{-19}\times 750}=2.23T$