Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1152: 97a

Answer

$\gamma = 534$

Work Step by Step

We can find $\gamma$: $K = mc^2(\gamma-1)$ $\frac{K}{mc^2} = \gamma-1$ $\gamma = \frac{K}{mc^2}+1$ $\gamma = \frac{500\times 10^9~eV}{938\times 10^6~eV}+1$ $\gamma = 534$
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