Answer
$m=88kg$
Work Step by Step
We first convert KwH to J:
$E=2.2\times 10^{12}KW.h=2.2\times 10^{12}\times 1000\times 3600$
$E=7.92\times 10^{18}J$
We know that:
$E=mc^2$
$m=\frac{E}{c^2}$
We plug in the known values to obtain:
$m=\frac{7.92\times 10^{18}}{(3\times 10^8)^2}=88kg$
