Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 3 - Vectors - Problems - Page 61: 78

Answer

36.6

Work Step by Step

$|\vec{a}\times(\vec{b}\times\vec{a})|=a\,|\vec{b}\times\vec{a}|\sin\theta$ where $\theta$ is the angle between $\vec{a}$ and $(\vec{b}\times\vec{a})$. As $\vec{b}\times\vec{a}$ is a vector perpendicular to both $\vec{b}$ and $\vec{a}$, we have $|\vec{a}\times(\vec{b}\times\vec{a})|=a\,|\vec{b}\times\vec{a}|\times\sin 90^{\circ}=a\,|\vec{b}\times\vec{a}|$ $=a(ba\sin\beta)$ where $\beta$ is the angle between $\vec{b}$ and $\vec{a}$. Given: a=3.90, b=2.70 and $\beta=63.0^{\circ}$. Therefore, $|\vec{a}\times(\vec{b}\times\vec{a})|=3.90(2.70\times3.90\times\sin63^{\circ})=36.6$
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