Answer
(i) $0.954$ $m$
Work Step by Step
The ant's net displacement can be express by the following vector
$\vec d=0.517\hat i+0.802\hat j$
$\therefore$ the magnitude of the ant's net displacement is
$|\vec d|=\sqrt {(0.517)^{2}+0.802^{2}}$ $m$
$|\vec d|\approx0.954$ $m$
