Answer
(j) $57.19^{\circ}$ north of east
Work Step by Step
The ant's net displacement can be express by the following vector
$\vec d=0.517\hat i+0.802\hat j$
Let, the displacement vector $\vec d$ makes an angle $\theta$ with positive $x$ axis. Then,
$\tan \theta =\frac{0.802}{0.517}$
or, $\theta=\tan^{-1}(\frac{0.802}{0.517})$
or, $\theta\approx 57.19^{\circ}$
Therefore, the direction of the ant’s net displacement is $57.19^{\circ}$ north of east.
