Answer
$2.0\hat{k}$
Work Step by Step
$\vec{a}\times\vec{b}=\begin{vmatrix}\hat{i}&\hat{j}&\hat{k}\\3.0&5.0&0\\2.0&4.0&0\end{vmatrix}$
$=\hat{k}(12-10)+0+0$ (expanding along column 3)
$= 2.0\hat{k}$
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