Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 3 - Vectors - Problems - Page 60: 66h

Answer

$$|\vec{a} \times \vec{b}|=a b$$

Work Step by Step

The vectors can be written as $\vec{a}=a \hat{\mathrm{i}}$ and $\vec{b}=b \hat{\mathrm{j}}$ where $a, b>0$ since $\sin 90^{\circ}=1,$ Eq. $3-24$ gives $|\vec{a} \times \vec{b}|=a b$ where $a$ is the magnitude of $\vec{a}$ $\therefore |\vec{a} \times \vec{b}|=|\vec{b} \times \vec{a}|=a b$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.